(1/2)*(7-4x)*(2x)=7x-4x^2

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Solution for (1/2)*(7-4x)*(2x)=7x-4x^2 equation: 



(1/2)*(7-4x)*(2x)=7x-4x^2

We move all terms to the left:

(1/2)*(7-4x)*(2x)-(7x-4x^2)=0



Domain of the equation: 2)*(7-4x)*2x!=0

x∈R



We add all the numbers together, and all the variables

-(7x-4x^2)+(+1/2)*(-4x+7)*2x=0

We get rid of parentheses

4x^2-7x+(+1/2)*(-4x+7)*2x=0

We multiply all the terms by the denominator


4x^2*2)*(-4x+7)*2x-7x*2)*(-4x+7)*2x+(+1=0

Wy multiply elements

8x^4-4x+7)*2x-7x*2)*(-4x+7)*2x+(+1=0

We do not support expression: x^4

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